Optimal. Leaf size=185 \[ -i b d e \text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right )-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+2 d e \log (x) \left (a+b \sin ^{-1}(c x)\right )+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )-\frac{b c d^2 \sqrt{1-c^2 x^2}}{2 x}+\frac{b e^2 x \sqrt{1-c^2 x^2}}{4 c}-\frac{b e^2 \sin ^{-1}(c x)}{4 c^2}-i b d e \sin ^{-1}(c x)^2+2 b d e \sin ^{-1}(c x) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )-2 b d e \log (x) \sin ^{-1}(c x) \]
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Rubi [A] time = 0.338032, antiderivative size = 185, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 14, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.667, Rules used = {266, 43, 4731, 12, 6742, 264, 321, 216, 2326, 4625, 3717, 2190, 2279, 2391} \[ -i b d e \text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right )-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+2 d e \log (x) \left (a+b \sin ^{-1}(c x)\right )+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )-\frac{b c d^2 \sqrt{1-c^2 x^2}}{2 x}+\frac{b e^2 x \sqrt{1-c^2 x^2}}{4 c}-\frac{b e^2 \sin ^{-1}(c x)}{4 c^2}-i b d e \sin ^{-1}(c x)^2+2 b d e \sin ^{-1}(c x) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )-2 b d e \log (x) \sin ^{-1}(c x) \]
Antiderivative was successfully verified.
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Rule 266
Rule 43
Rule 4731
Rule 12
Rule 6742
Rule 264
Rule 321
Rule 216
Rule 2326
Rule 4625
Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{\left (d+e x^2\right )^2 \left (a+b \sin ^{-1}(c x)\right )}{x^3} \, dx &=-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )+2 d e \left (a+b \sin ^{-1}(c x)\right ) \log (x)-(b c) \int \frac{-\frac{d^2}{x^2}+e^2 x^2+4 d e \log (x)}{2 \sqrt{1-c^2 x^2}} \, dx\\ &=-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )+2 d e \left (a+b \sin ^{-1}(c x)\right ) \log (x)-\frac{1}{2} (b c) \int \frac{-\frac{d^2}{x^2}+e^2 x^2+4 d e \log (x)}{\sqrt{1-c^2 x^2}} \, dx\\ &=-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )+2 d e \left (a+b \sin ^{-1}(c x)\right ) \log (x)-\frac{1}{2} (b c) \int \left (-\frac{d^2}{x^2 \sqrt{1-c^2 x^2}}+\frac{e^2 x^2}{\sqrt{1-c^2 x^2}}+\frac{4 d e \log (x)}{\sqrt{1-c^2 x^2}}\right ) \, dx\\ &=-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )+2 d e \left (a+b \sin ^{-1}(c x)\right ) \log (x)+\frac{1}{2} \left (b c d^2\right ) \int \frac{1}{x^2 \sqrt{1-c^2 x^2}} \, dx-(2 b c d e) \int \frac{\log (x)}{\sqrt{1-c^2 x^2}} \, dx-\frac{1}{2} \left (b c e^2\right ) \int \frac{x^2}{\sqrt{1-c^2 x^2}} \, dx\\ &=-\frac{b c d^2 \sqrt{1-c^2 x^2}}{2 x}+\frac{b e^2 x \sqrt{1-c^2 x^2}}{4 c}-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )-2 b d e \sin ^{-1}(c x) \log (x)+2 d e \left (a+b \sin ^{-1}(c x)\right ) \log (x)+(2 b d e) \int \frac{\sin ^{-1}(c x)}{x} \, dx-\frac{\left (b e^2\right ) \int \frac{1}{\sqrt{1-c^2 x^2}} \, dx}{4 c}\\ &=-\frac{b c d^2 \sqrt{1-c^2 x^2}}{2 x}+\frac{b e^2 x \sqrt{1-c^2 x^2}}{4 c}-\frac{b e^2 \sin ^{-1}(c x)}{4 c^2}-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )-2 b d e \sin ^{-1}(c x) \log (x)+2 d e \left (a+b \sin ^{-1}(c x)\right ) \log (x)+(2 b d e) \operatorname{Subst}\left (\int x \cot (x) \, dx,x,\sin ^{-1}(c x)\right )\\ &=-\frac{b c d^2 \sqrt{1-c^2 x^2}}{2 x}+\frac{b e^2 x \sqrt{1-c^2 x^2}}{4 c}-\frac{b e^2 \sin ^{-1}(c x)}{4 c^2}-i b d e \sin ^{-1}(c x)^2-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )-2 b d e \sin ^{-1}(c x) \log (x)+2 d e \left (a+b \sin ^{-1}(c x)\right ) \log (x)-(4 i b d e) \operatorname{Subst}\left (\int \frac{e^{2 i x} x}{1-e^{2 i x}} \, dx,x,\sin ^{-1}(c x)\right )\\ &=-\frac{b c d^2 \sqrt{1-c^2 x^2}}{2 x}+\frac{b e^2 x \sqrt{1-c^2 x^2}}{4 c}-\frac{b e^2 \sin ^{-1}(c x)}{4 c^2}-i b d e \sin ^{-1}(c x)^2-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )+2 b d e \sin ^{-1}(c x) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )-2 b d e \sin ^{-1}(c x) \log (x)+2 d e \left (a+b \sin ^{-1}(c x)\right ) \log (x)-(2 b d e) \operatorname{Subst}\left (\int \log \left (1-e^{2 i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )\\ &=-\frac{b c d^2 \sqrt{1-c^2 x^2}}{2 x}+\frac{b e^2 x \sqrt{1-c^2 x^2}}{4 c}-\frac{b e^2 \sin ^{-1}(c x)}{4 c^2}-i b d e \sin ^{-1}(c x)^2-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )+2 b d e \sin ^{-1}(c x) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )-2 b d e \sin ^{-1}(c x) \log (x)+2 d e \left (a+b \sin ^{-1}(c x)\right ) \log (x)+(i b d e) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 i \sin ^{-1}(c x)}\right )\\ &=-\frac{b c d^2 \sqrt{1-c^2 x^2}}{2 x}+\frac{b e^2 x \sqrt{1-c^2 x^2}}{4 c}-\frac{b e^2 \sin ^{-1}(c x)}{4 c^2}-i b d e \sin ^{-1}(c x)^2-\frac{d^2 \left (a+b \sin ^{-1}(c x)\right )}{2 x^2}+\frac{1}{2} e^2 x^2 \left (a+b \sin ^{-1}(c x)\right )+2 b d e \sin ^{-1}(c x) \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )-2 b d e \sin ^{-1}(c x) \log (x)+2 d e \left (a+b \sin ^{-1}(c x)\right ) \log (x)-i b d e \text{Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )\\ \end{align*}
Mathematica [A] time = 0.333032, size = 159, normalized size = 0.86 \[ \frac{1}{4} \left (-4 i b d e \text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right )-\frac{2 a d^2}{x^2}+8 a d e \log (x)+2 a e^2 x^2+b \sin ^{-1}(c x) \left (-\frac{e^2}{c^2}+8 d e \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )-\frac{2 d^2}{x^2}+2 e^2 x^2\right )-\frac{2 b c d^2 \sqrt{1-c^2 x^2}}{x}+\frac{b e^2 x \sqrt{1-c^2 x^2}}{c}-4 i b d e \sin ^{-1}(c x)^2\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.371, size = 248, normalized size = 1.3 \begin{align*}{\frac{a{x}^{2}{e}^{2}}{2}}-{\frac{a{d}^{2}}{2\,{x}^{2}}}+2\,aed\ln \left ( cx \right ) -ibde \left ( \arcsin \left ( cx \right ) \right ) ^{2}+{\frac{b{e}^{2}x}{4\,c}\sqrt{-{c}^{2}{x}^{2}+1}}+{\frac{b\arcsin \left ( cx \right ){x}^{2}{e}^{2}}{2}}-{\frac{b{e}^{2}\arcsin \left ( cx \right ) }{4\,{c}^{2}}}+{\frac{i}{2}}{c}^{2}b{d}^{2}-{\frac{bc{d}^{2}}{2\,x}\sqrt{-{c}^{2}{x}^{2}+1}}-{\frac{b{d}^{2}\arcsin \left ( cx \right ) }{2\,{x}^{2}}}+2\,bed\arcsin \left ( cx \right ) \ln \left ( 1-icx-\sqrt{-{c}^{2}{x}^{2}+1} \right ) +2\,bed\arcsin \left ( cx \right ) \ln \left ( 1+icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) -2\,ibed{\it polylog} \left ( 2,-icx-\sqrt{-{c}^{2}{x}^{2}+1} \right ) -2\,ibed{\it polylog} \left ( 2,icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{2} \, a e^{2} x^{2} - \frac{1}{2} \, b d^{2}{\left (\frac{\sqrt{-c^{2} x^{2} + 1} c}{x} + \frac{\arcsin \left (c x\right )}{x^{2}}\right )} + 2 \, a d e \log \left (x\right ) - \frac{a d^{2}}{2 \, x^{2}} + \int \frac{{\left (b e^{2} x^{2} + 2 \, b d e\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{a e^{2} x^{4} + 2 \, a d e x^{2} + a d^{2} +{\left (b e^{2} x^{4} + 2 \, b d e x^{2} + b d^{2}\right )} \arcsin \left (c x\right )}{x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b \operatorname{asin}{\left (c x \right )}\right ) \left (d + e x^{2}\right )^{2}}{x^{3}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x^{2} + d\right )}^{2}{\left (b \arcsin \left (c x\right ) + a\right )}}{x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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